DISCRETE MATHEMATICS(PART-02)
OBJECTIVE GENERAL KNOWLEDGE - DISCRETE MATHEMATICS
- A set of formulae A, B, C, D,......,R is said to be inconsistent if
- their disjunction is a tautology
- their conjunction is a tautology
- their conjunction is a contradiction
- their disjunction is a contradiction
- (x)(A(x) → B is equivalent to
- (∃x) (A(x) → B)
- ((∃x) A(x) → B)
- ((x)(A(x)→B)
- Which of the following propositions are equivalent over the universe of integers,. (i) 0< n^2 ≤ 4. (ii) 0< n^3 ≤ 8. (iii) 0< n ≤ 2
- (i) and (ii) are equivalent
- (i) and (iii) are equivalent
- all are equivalent
- (ii) and (iii) are equivalent
- Let L(x, y) be the statement “x loves y,” where the domain for both x and y consists of all people in the world. Use quantifiers to express, “Joy is loved by everyone.”
- ∃x ¬L(Joy, x)
- ∃y∀x L(x, y)
- ∀x L(x, Joy)
- ∀y L(Joy,y)
- An Open statement is a declarative sentence
- that is a tf- statement when each of its symbols is replaced by a specific object from a designated set
- that has no symbols
- that is a tf- statement
- that is a closed statement
- If P→(Q→S) 0s a valid from P→(Q→R) and Q→(R→S), then using CP rule, which is valid inference from the premises P, P→(Q→R) and Q→(R→S)
- P→S
- P→Q
- Q→S
- P→(Q→S)
- What rules of inference are used in this argument? “All students in this science class has taken a course in physics” and “Marry is a student in this class” imply the conclusion “Marry has taken a course in physics.”
- Existential specification
- Existential generalization
- Universal Specification
- Universal generalization
- Let domain of m includes all students, P (m) be the statement “m spends more than 2 hours in playing polo”. Express ∀m ¬P (m) quantification in English.
- No student spends more than 2 hours in playing polo
- There is a student who does not spend more than 2 hours in playing polo
- All students spends more than 2 hours in playing polo
- A student is there who spends more than 2 hours in playing polo
- “Parul is out for a trip or it is not snowing” and “It is snowing or Raju is playing chess” imply that
- Parul is out for a trip or Raju is playing chess
- Parul is out for a trip and Raju is playing chess
- Parul is out for trip
- Raju is playing chess
- The truth value of ∀n(n + 1 > n) if the domain consists of all real numbers is true.
- True
- False
- If monkeys can fly, then 1+1 = 3.
- True
- False
- Using DeMorgan's law find the negation of the given statement : "Carlos will bicycle or run tomorrow"
- Carlos will not bicycle tomorrow and carlos will not run tomorrow
- Carlos will not bicycle tomorrow and carlos will run tomorrow
- Carlos will bicycle tomorrow and carlos will not run tomorrow
- “Match will be played only if it is not a humid day.” The negation of this statement is? (a) Match will be played but it is a humid day . (b) Match will be played or it is a humid day.
- None of the statement
- Both statement (a) and statement (b)
- Statement (a) only
- Statement (b) only
- The relation "divides" on the set of all positive integers is
- equivalence relation
- Symmetric
- Not reflexive
- Not transitive
- Let A= set of all real numbers, B = set of all positive real numbers; let f(a) = |a|, then inverse of f exist
- True
- False
- The recurrence relation for the Fibonacci sequence is
- F(n)=F(n-1) - F(n-2)
- No recurrence relation
- F(n)=F(n-1) + 2
- F(n)=F(n-1) + F(n-2)
- The generating function for the sequence a[ n ] = 9Cn , n=0,1, 2, 3,.... is
- (1+x)^9
- (1+x)^-9
- (1-x)^9
- (1-x)^-9
- Any connected bi-partite graph is uniquely
- 2 - colourable
- 3 - colourable
- 5 - colourable
- 4 - colourable
- Every M-augmenting path is an M-alternating path
- True
- False
- If a ≤≤ x, b ≤≤ x then
- aΛb ≤ x aΛb ≤ x
- aVb ≤ x aVb ≤ x
- aΛb ≥ x aΛb ≥ x
- aVb ≥ x aVb ≥ x
- The chain(Z,≤)(Z,≤) contains
- contains neither the least element nor the greatest element
- greatest but not the least element
- contains both the least and the greatest element
- least but not the greatest element
- The absorption law is
- aΛa=aaΛa=a
- aΛb=bΛaaΛb=bΛa
- (aΛb)Λc=aΛ(bΛc)(aΛb)Λc=aΛ(bΛc)
- aΛ(aVb)=aaΛ(aVb)=a
- Let(L,≤)(L,≤) be a lattice . Assume aΛb=a aΛb=a
- a = b
- a≤b
- a≠b
- a≥b
- Use quantifiers and predicates with more than one variable to express, “There is a pupil in this lecture who has taken at least one course in Discrete Maths.”
- ∃x∀yP(x, y), where P (x, y) is “x has taken y,” the domain for x consists of all pupil in this class, and the domain for y consists of all Discrete Maths lectures.
- ∃x∃yP (x, y), where P (x, y) is “x has taken y,” the domain for x consists of all Discrete Maths lectures, and the domain for y consists of all pupil in this class.
- ∃x∃yP (x, y), where P (x, y) is “x has taken y,” the domain for x consists of all pupil in this class, and the domain for y consists of all Discrete Maths lectures.
- ∀x∀yP(x, y), where P (x, y) is “x has taken y,” the domain for x consists of all pupil in this class, and the domain for y consists of all Discrete Maths lectures.
- Identify the which of the following is a tautology
- ¬(x)A(x) = (∃x)(∃x) (¬A(x))
- ¬(x)A(x) = (∃x)(∃x) (A(x))
- ¬(x)A(x) = (x)(¬A(x))
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